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Read the following passage: An organization conducted bike race under two different categories – Boys and Girls. There were 28 participants in all. Among all of them - Mathematics

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Question

Read the following passage:

An organization conducted bike race under two different categories – Boys and Girls. There were 28 participants in all. Among all of them, finally three from category 1 and two from category 2 were selected for the final race. Ravi forms two sets B and G with these participants for his college project.
Let B = {b1, b2, b3} and G = {g1, g2}, where B represents the set of Boys selected and G the set of Girls selected for the final race.

Based on the above information, answer the following questions:

  1. How many relations are possible from B to G? (1)
  2. Among all the possible relations from B to G, how many functions can be formed from B to G? (1)
  3. Let R : B `rightarrow` B be defined by R = {(x, y) : x and y are students of the same sex}. Check if R is an equivalence relation. (2)
    OR
    A function f : B `rightarrow` G be defined by f = {(b1, g1), (b2, g2), (b3, g1)}. Check if f is bijective. Justify your answer. (2)
Sum
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Solution

  1. Number of possible relations from B `rightarrow` G
    = `2^(n(B) xx n(G))`
    = 23 × 2
    = 26
    = 64.


  2. Every element of set B has two options to map in set G i.e., B1 can go to G1 and G2.
    So, 2 ways (i.e., two functions).
    ∴ Total function = 2 × 2 × 2 = 8
  3. R : B `rightarrow` B
    R = {(x, y) : x and y are students of the same sex}
    (b1, b1) ∈ R   ...(Reflexive)
    (b1, b2) ∈ R `\implies` (b2, b1) ∈ R  ...(Symmetric)
    If (b1, b2) ∈ R ∧ (b2, b3) ∈ R
    `\implies` (b1, b3) ∈ R   ...(Transitive)
    `\implies` It is an equivalence relation.
    OR
    Given, B = {b1, b2, b3} and G = {g1, g2}
    f = {(b1, g1), (b2, g2), (b3, g1)}
    Since b1 and b3 both are related to same element g1.
    So f is not bijective (one-one).
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2022-2023 (March) Delhi Set 1

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