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Question
Prove that:
(i) ∆ ABC ≅ ∆ ADC
(ii) ∠B = ∠D
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Solution
Proof:
(i) In ∆ ABC and ∆ ADC
AC = AC ...........(common)
AB = DC ............(given)
BC = AD ...........(given)
∴ ∆ ABC ≅ ∆ ADC ................(S.S.S. Axiom)
(ii) Hence ∠B = ∠D ...........(c.p.c.t.)
Hence proved.
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