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Question
In ΔABC and ΔPQR and, AB = PQ, BC = QR and CB and RQ are extended to X and Y respectively and ∠ABX = ∠PQY. = Prove that ΔABC ≅ ΔPQR.
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Solution
In ΔABC and ΔPQR and
AB = PQ
BC = QR
∠ABX + ∠ABC
= ∠PQY + ∠PQR
= 180°
∠ABX = ∠PQY
⇒ ∠ABC = ∠PQR
Therefore,
ΔABC ≅ΔPQR ....(SAS criteria).
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