Advertisements
Advertisements
Question
PQRS is a quadrilateral and T and U are points on PS and RS respectively such that PQ = RQ, ∠PQT = ∠RQU and ∠TQS = ∠UQS. Prove that QT = QU.
Advertisements
Solution
∠PQT = ∠RQU .....(i)
∠TQS = ∠UQS .....(ii)
Adding (i) and (ii)
∠PQS = ∠RQS
In ΔPQS and ΔRQS
∠PQS = ∠RQS
PQ = RQ ...(given)
QS = QS ...(common)
Therefore, ΔPQS ≅ ΔRQS ...(SAS criteria)
Hence, ∠QPS = ∠QRS
Now in ΔPQT and ΔRQU
∠QPS = ∠QRS
PQ = RQ ...(given)
∠PQT = ∠RQU ...(given)
Therefore, ΔPQT ≅ ΔRQU ...ASA criteria)
Hence, QT =QU.
APPEARS IN
RELATED QUESTIONS
If ΔDEF ≅ ΔBCA, write the part(s) of ΔBCA that correspond to `bar(EF)`
If ΔDEF ≅ ΔBCA, write the part(s) of ΔBCA that correspond to `bar(DF)`
Find the measure of each angle of an equilateral triangle.
On the sides AB and AC of triangle ABC, equilateral triangle ABD and ACE are drawn. Prove that:
- ∠CAD = ∠BAE
- CD = BE
In the following diagram, ABCD is a square and APB is an equilateral triangle.
(i) Prove that: ΔAPD≅ ΔBPC
(ii) Find the angles of ΔDPC.
The following figure has shown a triangle ABC in which AB = AC. M is a point on AB and N is a point on AC such that BM = CN.
Prove that: (i) AM = AN (ii) ΔAMC ≅ ΔANB

Which of the following pairs of triangles are congruent? Give reasons
ΔABC;(AB = 8cm,BC = 6cm,∠B = 100°);
ΔPQR;(PQ = 8cm,RP = 5cm,∠Q = 100°).
In the figure, ∠BCD = ∠ADC and ∠ACB =∠BDA. Prove that AD = BC and ∠A = ∠B.
Sides, AB, BC and the median AD of ΔABC are equal to the two sides PQ, QR and the median PM of ΔPQR. Prove that ΔABC ≅ ΔPQR.

Without drawing the triangles write all six pairs of equal measures in the following pairs of congruent triangles.
∆XYZ ≅ ∆MLN
