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Question
∆PQR ~ ∆LTR. In ∆PQR, PQ = 4.2 cm, QR = 5.4 cm, PR = 4.8 cm. Construct ∆PQR and ∆LTR, such that `"PQ"/"LT" = 3/4`.
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Solution
Rough figure:
Steps of construction:
- Draw ΔPQR such that PQ = 4.2 cm, QR = 5.4 cm and PR = 4.8 cm.
- Draw a ray at point R, making a suitable angle with seg RQ.
- Take equal parts RR1, R1R2, R2R3, R3R4 on ray RX.
- Join the points Q and R3.
- Draw seg TR4 || seg QR3.
- Draw seg LT || seg PQ.
Construction:
Notes
- For drawing ΔPRQ of given measures = 1 mark
- For drawing acute angle at point R = 0.5 mark
- To mark points R1, R2, R3, R4 on ray RX at equal distance from point R = 0.5 mark
- To join seg R3Q and to draw parallel seg R4T to seg R3Q = 0.5 mark
- To draw parallel seg to PQ at point T = 0.5 mark
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