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Pooja Borrowed Rs 15,000 from Sonali at 11% P.A. Compound Interest. - Mathematics

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Question

Pooja borrowed Rs 15,000 from Sonali at 11% p.a. compound interest. If she repays Rs 7,550 at the end of first year and Rs 6,101 at the end of second year, find the amount Pooja needs to give to Sonali at the end of third year to clear her debt.

Sum
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Solution

P = Rs. 15,000, R = 11 °/o p.a.

Interest for first year 

`= ("Rs"  15000 xx 11 xx 1)/100`

= Rs, 1650 
Amount due after 1st year

= Rs. 15,000 + Rs. 1,650 =Rs 16,650 

Amount paid after 1st year= Rs. 7,550 

Balance amount= Rs. 16,650 - Rs. 7,550 =Rs. 9, 100 

Interest for second year 
`=("Rs"  9100 xx 11 xx 1)/100`

=Rs  1001

Amount paid after 2nd year = Rs. 61 10 1 

Balance amount = Rs. 10, 101 - Rs. 61 101 =Rs. 4,000 

Interest for third year 

= `("Rs"  4000 xx 11 xx 1)/100`

= Rs 440 
Amount due after 3rd year

= Rs. 4,000 + Rs. 440 =Rs 4,440 

Pooja needs to pay Rs 4,440 to Sonali at the end of third year to clear her debt. 

shaalaa.com
Concept of Compound Interest - Compound Interest as a Repeated Simple Interest Computation with a Growing Principal
  Is there an error in this question or solution?
Chapter 1: Compound Interest - Exercise 1.2 [Page 8]

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Frank Mathematics - Part 2 [English] Class 10 ICSE
Chapter 1 Compound Interest
Exercise 1.2 | Q 4 | Page 8

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