Advertisements
Advertisements
Question
Points A(4, 3), B(6, 4), C(5, –6) and D(–3, 5) are the vertices of a parallelogram.
Options
True
False
Advertisements
Solution
This statement is False.
Explanation:
Now, distance between A(4, 3) and B(6, 4),
AB = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
AB = `sqrt((6 - 4)^2 + (4 - 3)^2`
= `sqrt(2^2 + 1^2)`
= `sqrt(5)`
Distance between B(6, 4) and C(5, – 6),
BC = `sqrt((5 - 6)^2 + (-6 - 4)^2`
= `sqrt((-1)^2 + (-10)^2`
= `sqrt(1 + 100)`
= `sqrt(101)`
Distance between C(5, – 6) and D(– 3, 5),
CD = `sqrt((-3 - 5)^2 + (5 + 6)^2`
= `sqrt((-8)^2 + (11)^2`
= `sqrt(64 + 121)`
= `sqrt(185)`
Distance between D(– 3, 5) and A(4, 3),
DA = `sqrt((4 + 3)^2 + (3 - 5)^2`
= `sqrt(7^2 + (-2)^2`
= `sqrt(49 + 4)`
= `sqrt(53)`
In parallelogram, opposite sides are equal.
Here, we see that all sides AB, BC, CD and DA are different.
Hence, given vertices are not the vertices of a parallelogram.
APPEARS IN
RELATED QUESTIONS
Given a line segment AB joining the points A(–4, 6) and B(8, –3). Find
1) The ratio in which AB is divided by y-axis.
2) Find the coordinates of the point of intersection.
3) The length of AB.
If the points (2, 1) and (1, -2) are equidistant from the point (x, y), show that x + 3y = 0.
Find the distance between the points
A(1,-3) and B(4,-6)
Find the distance between the points
P(a sin ∝,a cos ∝ )and Q( acos ∝ ,- asin ∝)
If the point A(x,2) is equidistant form the points B(8,-2) and C(2,-2) , find the value of x. Also, find the value of x . Also, find the length of AB.
Using the distance formula, show that the given points are collinear:
(1, -1), (5, 2) and (9, 5)
Determine whether the points are collinear.
L(–2, 3), M(1, –3), N(5, 4)
Find the distances between the following point.
R(–3a, a), S(a, –2a)
Find the distance between the following pairs of point in the coordinate plane :
(4 , 1) and (-4 , 5)
Find the distance of a point (12 , 5) from another point on the line x = 0 whose ordinate is 9.
Find the coordinates of O, the centre passing through A( -2, -3), B(-1, 0) and C(7, 6). Also, find its radius.
Find the distance between the following pairs of points:
(–3, 6) and (2, –6)
KM is a straight line of 13 units If K has the coordinate (2, 5) and M has the coordinates (x, – 7) find the possible value of x.
The distance between point P(2, 2) and Q(5, x) is 5 cm, then the value of x = ______.
Find distance between point A(7, 5) and B(2, 5).
Find distance of point A(6, 8) from origin.
Find distance between point A(–1, 1) and point B(5, –7):
Solution: Suppose A(x1, y1) and B(x2, y2)
x1 = –1, y1 = 1 and x2 = 5, y2 = –7
Using distance formula,
d(A, B) = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
∴ d(A, B) = `sqrt(square +[(-7) + square]^2`
∴ d(A, B) = `sqrt(square)`
∴ d(A, B) = `square`
The distance of the point (α, β) from the origin is ______.
If the distance between the points (x, -1) and (3, 2) is 5, then the value of x is ______.
|
Case Study Trigonometry in the form of triangulation forms the basis of navigation, whether it is by land, sea or air. GPS a radio navigation system helps to locate our position on earth with the help of satellites. |
- Make a labelled figure on the basis of the given information and calculate the distance of the boat from the foot of the observation tower.
- After 10 minutes, the guard observed that the boat was approaching the tower and its distance from tower is reduced by 240(`sqrt(3)` - 1) m. He immediately raised the alarm. What was the new angle of depression of the boat from the top of the observation tower?

