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Maharashtra State BoardSSC (English Medium) 10th Standard

Find the distances between the following point. R(–3a, a), S(a, –2a)

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Question

Find the distances between the following point.

R(–3a, a), S(a, –2a)

Sum
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Solution

R(–3a, a), S(a, –2a)

Let R (x1, y1) and S (x2, y2) be the given points.

∴ x1 = –3a, y1 = a, x2 = a, y2 = –2a

By distance formula,

 d(R, S) = \[\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\]

= \[\sqrt{\left[\mathrm{a-(-3a)}\right]^{2}+\left(-2\mathrm{a-a}\right)^{2}}\]

= \[\sqrt{\left(\mathrm{a + 3a}\right)^{2}+\left(-2\mathrm{a-a}\right)^{2}}\]

= \[\sqrt{\left(\mathrm{4a}\right)^{2}+\left(\mathrm{-3a}\right)^{2}}\]

= \[\sqrt{16\mathbf{a}^{2}+9\mathbf{a}^{2}}\]

= \[\sqrt{25\mathbf{a}^{2}}\]

= 5a

∴ d(R, S) = 5a units

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Chapter 5: Co-ordinate Geometry - Problem Set 5 [Page 122]

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Balbharati Geometry Mathematics 2 [English] Standard 10 Maharashtra State Board
Chapter 5 Co-ordinate Geometry
Problem Set 5 | Q 6.3 | Page 122

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