Advertisements
Advertisements
Question
Plot the points P(1, 0), Q(4, 0) and S(1, 3). Find the coordinates of the point R such that PQRS is a square.
Advertisements
Solution
In point P(1, 0), y-coordinate is zero, so it lies on x-axis.
In point Q(4, 0), y-coordinate is zero so it lies on x-axis.
In point S(1, 3), both coordinates are positive, so it lies in I quadrant.
On plotting these points, we get the following graph.

Now, take a point R on the graph such that PQRS is a square.
Then, all sides will be equal i.e., PQ = QR = RS = PS.
So, abscissa of R should be equal to abscissa of Q i.e., 4 and ordinate of R should be equal to ordinate of S i.e., 3.
Hence, the coordinates of R are (4, 3).
APPEARS IN
RELATED QUESTIONS
Plot the following points on the one and the same co-ordinate system.
A(1, 3), B(-3, -1), C(1, -4), D(-2, 3), E(0, -8), F(1, 0)
Plot the following point in the coordinate system and identify the quadrant.
T(3, 9)
Plot the following point in a graph sheet.
A(5, 2)
Find the quadrants without plotting the point on a graph sheet.
(5, 7)
Plot the following point in a graph sheet.
E(0, −5)
Find the quadrants without plotting the point on a graph sheet.
(−8, 0)
If P(–1, 1), Q(3, –4), R(1, –1), S(–2, –3) and T(–4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant are ______.
Plot the following points and check whether they are collinear or not:
(0, 0), (2, 2), (5, 5)
From the figure, answer the following:
Write the points whose abscissa is – 5.
Plot the points A(1, – 1) and B(4, 5). Extend this line segment and write the coordinates of a point on this line which lies outside the line segment AB.
