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प्रश्न
Plot the points P(1, 0), Q(4, 0) and S(1, 3). Find the coordinates of the point R such that PQRS is a square.
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उत्तर
In point P(1, 0), y-coordinate is zero, so it lies on x-axis.
In point Q(4, 0), y-coordinate is zero so it lies on x-axis.
In point S(1, 3), both coordinates are positive, so it lies in I quadrant.
On plotting these points, we get the following graph.
Now, take a point R on the graph such that PQRS is a square.
Then, all sides will be equal i.e., PQ = QR = RS = PS.
So, abscissa of R should be equal to abscissa of Q i.e., 4 and ordinate of R should be equal to ordinate of S i.e., 3.
Hence, the coordinates of R are (4, 3).
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संबंधित प्रश्न
Plot the following point on the graph paper:
(−4, 0)
Some points are shown in the following figure. With the help of it answer the following questions:
- Write the co-ordinates of the points Q and R.
- Write the co-ordinates of the points T and M.
- Which point lies in the third quadrant?
- Which are the points whose x and y co-ordinates are equal?
Plot the following point in the coordinate system and identify the quadrant.
T(3, 9)
Plot the following point in a graph sheet.
D(−1, −1)
Find the quadrants without plotting the point on a graph sheet
(−3, −5)
In the following figure, coordinates of P are ______.
Plot the following points and check whether they are collinear or not:
(1, 3), (– 1, – 1), (– 2, – 3)
From the figure, answer the following:
Write the points whose abscissa is – 5.
Plot the points A(1, – 1) and B(4, 5). Draw a line segment joining these points. Write the coordinates of a point on this line segment between the points A and B.
Plot the points A(1, – 1) and B(4, 5). Extend this line segment and write the coordinates of a point on this line which lies outside the line segment AB.
