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प्रश्न
Plot the points P(1, 0), Q(4, 0) and S(1, 3). Find the coordinates of the point R such that PQRS is a square.
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उत्तर
In point P(1, 0), y-coordinate is zero, so it lies on x-axis.
In point Q(4, 0), y-coordinate is zero so it lies on x-axis.
In point S(1, 3), both coordinates are positive, so it lies in I quadrant.
On plotting these points, we get the following graph.
Now, take a point R on the graph such that PQRS is a square.
Then, all sides will be equal i.e., PQ = QR = RS = PS.
So, abscissa of R should be equal to abscissa of Q i.e., 4 and ordinate of R should be equal to ordinate of S i.e., 3.
Hence, the coordinates of R are (4, 3).
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संबंधित प्रश्न
Plot the following point on the graph paper:
(−4, 0)
Write down the abscissa and ordinate of the following.
P
Plot the following point in a graph sheet.
B(−7, −3)
Plot the following point in a graph sheet.
C(−2, 4)
Plot the following point in a graph sheet.
F(2, 0)
Plot the following point in a graph sheet.
I(2, 3)
Plot the points (x, y) given by the following table:
| x | 2 | 4 | – 3 | – 2 | 3 | 0 |
| y | 4 | 2 | 0 | 5 | – 3 | 0 |
Plot the following points and check whether they are collinear or not:
(0, 0), (2, 2), (5, 5)
Plot the points (x, y) given by the following table. Use scale 1 cm = 0.25 units
| x | 1.25 | 0.25 | 1.5 | – 1.75 |
| y | – 0.5 | 1 | 1.5 | – 0.25 |
From the figure, answer the following:
Write the points whose ordinate is 0.
