Advertisements
Advertisements
Question
Plot the points A(1, – 1) and B(4, 5). Extend this line segment and write the coordinates of a point on this line which lies outside the line segment AB.
Advertisements
Solution
In point A(1, – 1), x-coordinate is positive and y-coordinate is negative, so it lies in IV quadrant.
In point B(4, 5), both coordinates are positive, so it lies in I quadrant.
On plotting these point, we get the following graph.
Extent the line segment AB.
Now, draw a perpendicular to x-axis from x = 5, say it intersects extended line segment at Q.
Again, draw a perpendicular to y-axis from Q and it intersects y-axis at y = 7.
Thus, we get the point Q(5, 7) which lies outside the line segment AB.
APPEARS IN
RELATED QUESTIONS
Plot the following point on the graph paper:
(7, −4)
Plot the following point on the graph paper:
(7, 0)
Write the equation of the line parallel to the Y-axis at a distance of 7 units from it to its left.
Write down the abscissa and ordinate of the following.
S
If the y-coordinate of a point is zero, then the point always lies ______
On plotting the points O(0, 0), A(3, 0), B(3, 4), C(0, 4) and joining OA, AB, BC and CO which of the following figure is obtained?
Plot the following point in a graph sheet.
B(−7, −3)
Plot the following point in a graph sheet.
H(−4, 0)
Plot the points (x, y) given by the following table:
| x | 2 | 4 | – 3 | – 2 | 3 | 0 |
| y | 4 | 2 | 0 | 5 | – 3 | 0 |
Plot the following points and check whether they are collinear or not:
(0, 0), (2, 2), (5, 5)
