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प्रश्न
Plot the points A(1, – 1) and B(4, 5). Extend this line segment and write the coordinates of a point on this line which lies outside the line segment AB.
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उत्तर
In point A(1, – 1), x-coordinate is positive and y-coordinate is negative, so it lies in IV quadrant.
In point B(4, 5), both coordinates are positive, so it lies in I quadrant.
On plotting these point, we get the following graph.
Extent the line segment AB.
Now, draw a perpendicular to x-axis from x = 5, say it intersects extended line segment at Q.
Again, draw a perpendicular to y-axis from Q and it intersects y-axis at y = 7.
Thus, we get the point Q(5, 7) which lies outside the line segment AB.
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संबंधित प्रश्न
Plot the following point on the graph paper:
(0, 7)
Plot the following point on the graph paper:
(0, −4)
Plot the following point in the coordinate system and identify the quadrant.
T(3, 9)
Write down the abscissa and ordinate of the following.
Q
Find the quadrants without plotting the point on a graph sheet
(4, −3)
Find the quadrants without plotting the point on a graph sheet.
(−9, 50)
Plot the following point in a graph sheet.
I(2, 3)
If P(5, 1), Q(8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the point(s) on the x-axis are ______.
Plot the following points and check whether they are collinear or not:
(1, 1), (2, – 3), (– 1, – 2)
From the figure, answer the following:
Write the points whose abscissa is – 5.
