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प्रश्न
Plot the points A(1, – 1) and B(4, 5). Extend this line segment and write the coordinates of a point on this line which lies outside the line segment AB.
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उत्तर
In point A(1, – 1), x-coordinate is positive and y-coordinate is negative, so it lies in IV quadrant.
In point B(4, 5), both coordinates are positive, so it lies in I quadrant.
On plotting these point, we get the following graph.
Extent the line segment AB.
Now, draw a perpendicular to x-axis from x = 5, say it intersects extended line segment at Q.
Again, draw a perpendicular to y-axis from Q and it intersects y-axis at y = 7.
Thus, we get the point Q(5, 7) which lies outside the line segment AB.
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संबंधित प्रश्न
Plot the following point on the graph paper:
(−5, −7)
Plot the following point on the graph paper:
(0, −4)
Plot the following points on the one and the same co-ordinate system.
A(1, 3), B(-3, -1), C(1, -4), D(-2, 3), E(0, -8), F(1, 0)
Write down the abscissa and ordinate of the following.
P
Plot the following points in the coordinate plane. Join them in order. What type of geometrical shape is formed?
(−3, 3) (2, 3) (−6, −1) (5, −1)
On plotting the points O(0, 0), A(3, 0), B(3, 4), C(0, 4) and joining OA, AB, BC and CO which of the following figure is obtained?
Plot the following point in a graph sheet.
A(5, 2)
Find the quadrants without plotting the point on a graph sheet.
(2, 0)
Find the quadrants without plotting the point on a graph sheet.
(−8, 0)
Plot the following point in a graph sheet.
J(8, −4)
