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प्रश्न
Plot the points A(1, – 1) and B(4, 5). Extend this line segment and write the coordinates of a point on this line which lies outside the line segment AB.
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उत्तर
In point A(1, – 1), x-coordinate is positive and y-coordinate is negative, so it lies in IV quadrant.
In point B(4, 5), both coordinates are positive, so it lies in I quadrant.
On plotting these point, we get the following graph.
Extent the line segment AB.
Now, draw a perpendicular to x-axis from x = 5, say it intersects extended line segment at Q.
Again, draw a perpendicular to y-axis from Q and it intersects y-axis at y = 7.
Thus, we get the point Q(5, 7) which lies outside the line segment AB.
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संबंधित प्रश्न
Plot the points (x, y) given in the following table on the plane, choosing suitable units of distance on the axes.
| x | -2 | -1 | 0 | 1 | 3 |
| y | 8 | 7 | -1.25 | 3 | -1 |
Plot the following point on the graph paper:
(4, −3)
Plot the following points in the coordinate plane. Join them in order. What type of geometrical shape is formed?
(0, 0) (−4, 0) (−4, −4) (0, −4)
If the y-coordinate of a point is zero, then the point always lies ______
Plot the following point in a graph sheet.
E(0, −5)
Plot the following point in a graph sheet.
I(2, 3)
If P(–1, 1), Q(3, –4), R(1, –1), S(–2, –3) and T(–4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant are ______.
In the following figure, the point identified by the coordinates (–5, 3) is ______.
Points A(5, 3), B(– 2, 3) and D(5, – 4) are three vertices of a square ABCD. Plot these points on a graph paper and hence find the coordinates of the vertex C.
From the figure, answer the following:
- Write the points whose abscissa is 0.
- Write the points whose ordinate is 0.
- Write the points whose abscissa is –5.
