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प्रश्न
Plot the points A(1, – 1) and B(4, 5). Extend this line segment and write the coordinates of a point on this line which lies outside the line segment AB.
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उत्तर
In point A(1, – 1), x-coordinate is positive and y-coordinate is negative, so it lies in IV quadrant.
In point B(4, 5), both coordinates are positive, so it lies in I quadrant.
On plotting these point, we get the following graph.
Extent the line segment AB.
Now, draw a perpendicular to x-axis from x = 5, say it intersects extended line segment at Q.
Again, draw a perpendicular to y-axis from Q and it intersects y-axis at y = 7.
Thus, we get the point Q(5, 7) which lies outside the line segment AB.
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संबंधित प्रश्न
Plot the following point on the graph paper:
(0, −4)
Plot the following point in the coordinate system and identify the quadrant.
T(3, 9)
Plot the following points in the coordinate plane. Join them in order. What type of geometrical shape is formed?
(0, 0) (−4, 0) (−4, −4) (0, −4)
Find the quadrants without plotting the point on a graph sheet
(3, −4)
Plot the following point in a graph sheet.
H(−4, 0)
Use the graph to determine the coordinates where each figure is located.
| a) Star | _______ |
| b) Bird | _______ |
| c) Red circle | _______ |
| d) Diamond | _______ |
| e) Triangle | _______ |
| f) Ant | _______ |
| g) Mango | _______ |
| h) Housefly | _______ |
| i) Medal | _______ |
| j) Spider | _______ |
If P(–1, 1), Q(3, –4), R(1, –1), S(–2, –3) and T(–4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant are ______.
In the following figure, the point identified by the coordinates (–5, 3) is ______.
Plot the points (x, y) given by the following table. Use scale 1 cm = 0.25 units
| x | 1.25 | 0.25 | 1.5 | – 1.75 |
| y | – 0.5 | 1 | 1.5 | – 0.25 |
From the figure, answer the following:
- Write the points whose abscissa is 0.
- Write the points whose ordinate is 0.
- Write the points whose abscissa is –5.
