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प्रश्न
Plot the points A(1, – 1) and B(4, 5). Draw a line segment joining these points. Write the coordinates of a point on this line segment between the points A and B.
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उत्तर
In point A(1, – 1), x-coordinate is positive and y-coordinate is negative, so it lies in IV quadrant.
In point B(4, 5), both coordinates are positive, so it lies in I quadrant.
On plotting these point, we get the following graph.
On joining the points A and B, we get the line segment AB.
Now, to find the coordinates of a point on this line segment between A and B draw a perpendicular to x-axis from x = 2 and 3.
Since, x = 2 and 3 lies between A and B say it intersect line segment AB at P and p'.
Now, draw a perpendicular to y-axis from P and p’, they intersect y-axis at y = 1 and 3, respectively.
Thus, we get points (2, 1) and (3, 3) which lie between line segment AB.
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संबंधित प्रश्न
Plot the following point on the graph paper:
(7, −4)
Plot the following point on the graph paper:
(−4, 0)
Write down the abscissa and ordinate of the following.
R
Plot the following point in a graph sheet.
F(2, 0)
Plot the following point in a graph sheet.
G(7, −4)
Find the quadrants without plotting the point on a graph sheet
(4, −3)
Plot the following points and check whether they are collinear or not:
(0, 0), (2, 2), (5, 5)
Plot the points (x, y) given by the following table. Use scale 1 cm = 0.25 units
| x | 1.25 | 0.25 | 1.5 | – 1.75 |
| y | – 0.5 | 1 | 1.5 | – 0.25 |
Taking 0.5 cm as 1 unit, plot the following points on the graph paper:
A(1, 3), B(– 3, – 1), C(1, – 4), D(– 2, 3), E(0, – 8), F(1, 0)
From the figure, answer the following:
Write the points whose abscissa is – 5.
