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Question
One number is seven times another. If their difference is 18, find the numbers
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Solution
Let the numbers be x & y
Given that one number is 7 times the other & that the difference is 18.
Let x = 7y
also, x – y = 18 ...(given)
Substituting for x in the above
We get 7y – y = 18
∴ 6y = 18
y = `18/6` = 3
∴ x = 7y = 7 × 3 = 21
The number are 3 & 21
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