Advertisements
Advertisements
प्रश्न
One number is seven times another. If their difference is 18, find the numbers
Advertisements
उत्तर
Let the numbers be x & y
Given that one number is 7 times the other & that the difference is 18.
Let x = 7y
also, x – y = 18 ...(given)
Substituting for x in the above
We get 7y – y = 18
∴ 6y = 18
y = `18/6` = 3
∴ x = 7y = 7 × 3 = 21
The number are 3 & 21
APPEARS IN
संबंधित प्रश्न
Subtract the second expression from the first.
(4xy − 9z); (3xy − 16z)
Solve:
(7m − 5n) − (−4n − 11m)
Solve:
(11m − 12n + 3p) − (9m + 7n − 8p)
Subtract: 13x + 12y – 5 from 27x + 5y – 43
Subtract:
5a2b2c2 from –7a2b2c2
Subtract:
6x2 – 4xy + 5y2 from 8y2 + 6xy – 3x2
Subtract:
2ab + 5bc – 7ac from 5ab – 2bc – 2ac + 10abc
The subtraction of 5 times of y from x is ______.
What should be subtracted from 2x3 – 3x2y + 2xy2 + 3y3 to get x3 – 2x2y + 3xy2 + 4y3?
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
(A + B) – C
