Advertisements
Advertisements
प्रश्न
From the sum of x2 – y2 – 1, y2 – x2 – 1 and 1 – x2 – y2 subtract –(1 + y2).
Advertisements
उत्तर
Sum of x2 – y2 – 1, y2 – x2 – 1 and 1 – x2 – y2 = x2 – y2 – 1 + y2 – x2 – 1 + 1 – x2 – y2
On combining the like terms,
= x2 – x2 – x2 – y2 + y2 – y2 – 1 – 1 + 1
= –x2 – y2 – 1
Now, subtract –(1 + y2) from –x2 – y2 – 1
= –x2 – y2 – 1 – [–(1 + y2)]
= – x2 – y2 – 1 + 1 + y2
= –x2 – y2 + y2 – 1 + 1
= –x2
APPEARS IN
संबंधित प्रश्न
Solve:
(7m − 5n) − (−4n − 11m)
Simplify: (x + y – z) + (3x – 5y + 7z) – (14x + 7y – 6z)
Subtract:
3t4 – 4t3 + 2t2 – 6t + 6 from – 4t4 + 8t3 – 4t2 – 2t + 11
Subtract:
2ab + 5bc – 7ac from 5ab – 2bc – 2ac + 10abc
Subtract the following expressions:
–a2 – ab from b2 + ab
Subtract the following expressions:
ab – bc – ca from –ab + bc + ca
How much is 21a3 – 17a2 less than 89a3 – 64a2 + 6a + 16?
To what expression must 99x3 – 33x2 – 13x – 41 be added to make the sum zero?
Subtract 9a2 – 15a + 3 from unity.
Subtract the sum of 12ab – 10b2 – 18a2 and 9ab + 12b2 + 14a2 from the sum of ab + 2b2 and 3b2 – a2.
