Advertisements
Advertisements
Question
From the sum of x2 – y2 – 1, y2 – x2 – 1 and 1 – x2 – y2 subtract –(1 + y2).
Advertisements
Solution
Sum of x2 – y2 – 1, y2 – x2 – 1 and 1 – x2 – y2 = x2 – y2 – 1 + y2 – x2 – 1 + 1 – x2 – y2
On combining the like terms,
= x2 – x2 – x2 – y2 + y2 – y2 – 1 – 1 + 1
= –x2 – y2 – 1
Now, subtract –(1 + y2) from –x2 – y2 – 1
= –x2 – y2 – 1 – [–(1 + y2)]
= – x2 – y2 – 1 + 1 + y2
= –x2 – y2 + y2 – 1 + 1
= –x2
APPEARS IN
RELATED QUESTIONS
Subtract: 4k from 12k
Subtract: 15q from 25q
Subtract: 7xyz from 17xyz
Subtract: 13x + 12y – 5 from 27x + 5y – 43
Subtract:
2ab2c2 + 4a2b2c – 5a2bc2 from –10a2b2c + 4ab2c2 + 2a2bc2
Subtract:
3t4 – 4t3 + 2t2 – 6t + 6 from – 4t4 + 8t3 – 4t2 – 2t + 11
Subtract the following expressions:
2(ab + bc + ca) from –ab – bc – ca
Subtract the following expressions:
4.5x5 – 3.4x2 + 5.7 from 5x4 – 3.2x2 – 7.3x
How much does 93p2 – 55p + 4 exceed 13p3 – 5p2 + 17p – 90?
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
A + B + C
