Advertisements
Advertisements
Question
From the sum of x2 – y2 – 1, y2 – x2 – 1 and 1 – x2 – y2 subtract –(1 + y2).
Advertisements
Solution
Sum of x2 – y2 – 1, y2 – x2 – 1 and 1 – x2 – y2 = x2 – y2 – 1 + y2 – x2 – 1 + 1 – x2 – y2
On combining the like terms,
= x2 – x2 – x2 – y2 + y2 – y2 – 1 – 1 + 1
= –x2 – y2 – 1
Now, subtract –(1 + y2) from –x2 – y2 – 1
= –x2 – y2 – 1 – [–(1 + y2)]
= – x2 – y2 – 1 + 1 + y2
= –x2 – y2 + y2 – 1 + 1
= –x2
APPEARS IN
RELATED QUESTIONS
Subtract the second expression from the first.
(5x + 4y + 7z); (x + 2y + 3z)
Solve the following equation.
5m − 4 = 1
Subtract: 3p + 5 from p – 2q + 7
When we subtract ‘a’ from ‘−a’, we get __________
If we subtract –3x2y2 from x2y2, then we get ______.
Subtract:
6x2 – 4xy + 5y2 from 8y2 + 6xy – 3x2
Subtract the following expressions:
–7p2qr from –3p2qr
Subtract the following expressions:
–4x2y – y3 from x3 + 3xy2 – x2y
Subtract the following expressions:
–2a2 – 2b2 from –a2 – b2 + 2ab
What should be subtracted from 2x3 – 3x2y + 2xy2 + 3y3 to get x3 – 2x2y + 3xy2 + 4y3?
