Advertisements
Advertisements
प्रश्न
Subtract the following expressions:
ab – bc – ca from –ab + bc + ca
Advertisements
उत्तर
We have, –ab + bc + ca – (ab – bc – ca)
= –ab + bc + ca – ab + bc + ca
On combining the like terms,
= –ab – ab + bc + bc + ca + ca
= –2ab + 2bc + 2ca
APPEARS IN
संबंधित प्रश्न
Subtract the second expression from the first.
(4xy − 9z); (3xy − 16z)
Solve:
(11m − 12n + 3p) − (9m + 7n − 8p)
Subtract: 4k from 12k
Subtract: 2y + z from 6z – 5y
When we subtract ‘a’ from ‘−a’, we get __________
Subtract:
2ab2c2 + 4a2b2c – 5a2bc2 from –10a2b2c + 4ab2c2 + 2a2bc2
Subtract the following expressions:
2(ab + bc + ca) from –ab – bc – ca
Subtract the following expressions:
11 – 15y2 from y3 – 15y2 – y – 11
How much does 93p2 – 55p + 4 exceed 13p3 – 5p2 + 17p – 90?
Subtract the sum of 12ab – 10b2 – 18a2 and 9ab + 12b2 + 14a2 from the sum of ab + 2b2 and 3b2 – a2.
