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प्रश्न
Subtract:
5a2b2c2 from –7a2b2c2
बेरीज
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उत्तर
We have,
5a2b2c2 and –7a2b2c2
The required difference is given by –7a2b2c2 – 5a2b2c2
= (–7 – 5)a2b2c2
= –12a2b2c2
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३०]
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संबंधित प्रश्न
Subtract the second expression from the first.
(14x2 + 8xy + 3y2); (26x2 − 8xy − 17y2)
Solve:
(7m − 5n) − (−4n − 11m)
Solve:
(11m − 12n + 3p) − (9m + 7n − 8p)
Subtract: 4k from 12k
Subtract: 13x + 12y – 5 from 27x + 5y – 43
Simplify: (x + y – z) + (3x – 5y + 7z) – (14x + 7y – 6z)
Subtract:
2ab + 5bc – 7ac from 5ab – 2bc – 2ac + 10abc
Subtracting a term from a given expression is the same as adding its additive inverse to the given expression.
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
B + C – A
From the sum of x2 – y2 – 1, y2 – x2 – 1 and 1 – x2 – y2 subtract –(1 + y2).
