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प्रश्न
Add:
3a(2b + 5c), 3c(2a + 2b)
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उत्तर
We have,
3a(2b + 5c) + 3c(2a + 2b)
= (6ab + 15ac) + (6ac + 6bc)
= 6ab + 15ac + 6ac + 6bc ...[Grouping like terms]
= 6ab + 21ac + 6bc
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संबंधित प्रश्न
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t – t2 – t3 – 14; 15t3 + 13 + 9t – 8t2; 12t2 – 19 – 24t and 4t – 9t2 + 19t3
