Advertisements
Advertisements
प्रश्न
Multiply: \[\left( \frac{x}{7} + \frac{x^2}{2} \right)by\left( \frac{2}{5} + \frac{9x}{4} \right)\]
Advertisements
उत्तर
To multiply the expressions, we will use the distributive law in the following way:
\[\left( \frac{x}{7} + \frac{x^2}{2} \right)\left( \frac{2}{5} + \frac{9x}{4} \right)\]
\[ = \frac{x}{7}\left( \frac{2}{5} + \frac{9x}{4} \right) + \frac{x^2}{2}\left( \frac{2}{5} + \frac{9x}{4} \right)\]
\[ = \frac{2x}{35} + \frac{9 x^2}{28} + \frac{x^2}{5} + \frac{9 x^3}{8}\]
\[ = \frac{2x}{35} + \left( \frac{45 + 28}{140} \right) x^2 + \frac{9 x^3}{8}\]
\[ = \frac{2x}{35} + \frac{73 x^2}{140} + \frac{9 x^2}{8}\]
Thus, the answer is \[\frac{2x}{35} + \frac{73 x^2}{140} + \frac{9 x^3}{8}\].
APPEARS IN
संबंधित प्रश्न
Subtract 4p2q − 3pq + 5pq2 − 8p + 7q − 10 from 18 − 3p − 11q + 5pq − 2pq2 + 5p2q
Simplify combining like terms: 3a - 2b - ab - (a - b + ab) + 3ab + b - a
Subtract: 4pq - 5q2 - 3p2 from 5p2 + 3q2 - pq
What should be added to x2 + xy + y2 to obtain 2x2 + 3xy?
What should be subtracted from 2a + 8b + 10 to get - 3a + 7b + 16?
Subtract the sum of 2x − x2 + 5 and − 4x − 3 + 7x2 from 5.
If x is a natural number, then x + 1 is its predecessor
Add:
2p4 – 3p3 + p2 – 5p + 7, –3p4 – 7p3 – 3p2 – p – 12
Sum of x2 + x and y + y2 is 2x2 + 2y2.
Add the following expressions:
p2 – 7pq – q2 and –3p2 – 2pq + 7q2
