Advertisements
Advertisements
प्रश्न
Multiply: \[\left( \frac{x}{7} + \frac{x^2}{2} \right)by\left( \frac{2}{5} + \frac{9x}{4} \right)\]
Advertisements
उत्तर
To multiply the expressions, we will use the distributive law in the following way:
\[\left( \frac{x}{7} + \frac{x^2}{2} \right)\left( \frac{2}{5} + \frac{9x}{4} \right)\]
\[ = \frac{x}{7}\left( \frac{2}{5} + \frac{9x}{4} \right) + \frac{x^2}{2}\left( \frac{2}{5} + \frac{9x}{4} \right)\]
\[ = \frac{2x}{35} + \frac{9 x^2}{28} + \frac{x^2}{5} + \frac{9 x^3}{8}\]
\[ = \frac{2x}{35} + \left( \frac{45 + 28}{140} \right) x^2 + \frac{9 x^3}{8}\]
\[ = \frac{2x}{35} + \frac{73 x^2}{140} + \frac{9 x^2}{8}\]
Thus, the answer is \[\frac{2x}{35} + \frac{73 x^2}{140} + \frac{9 x^3}{8}\].
संबंधित प्रश्न
Add: 14x + 10y - 12xy - 13, 18 - 7x - 10y + 8xy, 4xy
Add: x2 - y2 - 1 , y2 - 1 - x2, 1- x2 - y2
Subtract: - 5y2 from y2
If \[x + \frac{1}{x} = 12,\] find the value of \[x - \frac{1}{x} .\]
If x is a natural number, then x + 1 is its predecessor
Add: 2a + b + 3c and `"a" + 1/3"b" + 2/5"c"`
Add:
3a(a – b + c), 2b(a – b + c)
Add:
3a(2b + 5c), 3c(2a + 2b)
The expression 13 + 90 is a ______.
Add the following expressions:
x3 – x2y – xy2 – y3 and x3 – 2x2y + 3xy2 + 4y
