Advertisements
Advertisements
प्रश्न
Solve the following equation.
`4"x"+1/2=9/2`
Advertisements
उत्तर
`4"x"+1/2=9/2`
⇒ 4x = `9/2-1/2`
⇒ 4x = `(9-1)/2`
⇒ 4x = `8/2`
⇒ 4x = 4
⇒ x = `4/4`
⇒ x = 1
संबंधित प्रश्न
Add the following:
ab − bc, bc − ca, ca − ab
Subtract 3xy + 5yz − 7zx from 5xy − 2yz − 2zx + 10xyz.
Simplify combining like terms: - z2 + 13z2 − 5z + 7z3 − 15z
Subtract the sum of 2x − x2 + 5 and − 4x − 3 + 7x2 from 5.
If \[x - \frac{1}{x} = 3,\] find the values of \[x^2 + \frac{1}{x^2}\] and \[x^4 + \frac{1}{x^4} .\]
Find the expression to be added with 5a – 3b – 2c to get a – 4b – 2c?
Add:
9ax + 3by – cz, –5by + ax + 3cz
Add the following expressions:
p2 – q + r, q2 – r + p and r2 – p + q
Add the following expressions:
a2 + 3ab – bc, b2 + 3bc – ca and c2 + 3ca – ab
What should be added to x3 + 3x2y + 3xy2 + y3 to get x3 + y3?
