Advertisements
Advertisements
प्रश्न
Solve the following equation.
`4"x"+1/2=9/2`
Advertisements
उत्तर
`4"x"+1/2=9/2`
⇒ 4x = `9/2-1/2`
⇒ 4x = `(9-1)/2`
⇒ 4x = `8/2`
⇒ 4x = 4
⇒ x = `4/4`
⇒ x = 1
संबंधित प्रश्न
Subtract 4p2q − 3pq + 5pq2 − 8p + 7q − 10 from 18 − 3p − 11q + 5pq − 2pq2 + 5p2q
Add: -7mn + 5, 12mn + 2, 9mn - 8, -2mn - 3
Add: 14x + 10y - 12xy - 13, 18 - 7x - 10y + 8xy, 4xy
What should be taken away from 3x2 - 4y2 + 5xy + 20 to obtain - x2 - y2 + 6xy + 20?
Add the following algebraic expression:
\[\frac{11}{2}xy + \frac{12}{5}y + \frac{13}{7}x, - \frac{11}{2}y - \frac{12}{5}x - \frac{13}{7}xy\]
Subtract:
\[x^2 y - \frac{4}{5}x y^2 + \frac{4}{3}xy \text { from } \frac{2}{3} x^2 y + \frac{3}{2}x y^2 - \frac{1}{3}xy\]
Subtract the sum of 2x − x2 + 5 and − 4x − 3 + 7x2 from 5.
Add:
9p + 16q; 13p + 2q
Simplify: n + (m + 1) + (n + 2) + (m + 3) + (n + 4) + (m + 5)
