Advertisements
Advertisements
प्रश्न
From the sum of 3x - y + 11 and - y - 11, subtract 3x - y - 11.
Advertisements
उत्तर
(3x - y + 11) + (- y - 11)
= 3x - y + 11 - y - 11
= 3x - y - y + 11 - 11
= 3x - 2y
(3x - 2y) - (3x - y - 11)
= 3x - 2y - 3x + y + 11
= 3x - 3x - 2y + y + 11
= -y + 11
संबंधित प्रश्न
Add: -7mn + 5, 12mn + 2, 9mn - 8, -2mn - 3
Subtract: (a - b) from (a + b)
Add the following algebraic expression:
3a2b, − 4a2b, 9a2b
If \[x - \frac{1}{x} = 3,\] find the values of \[x^2 + \frac{1}{x^2}\] and \[x^4 + \frac{1}{x^4} .\]
Add:
3y2 − 10y + 16; 2y − 7
Add:
3a(a – b + c), 2b(a – b + c)
Add the following expressions:
x3 – x2y – xy2 – y3 and x3 – 2x2y + 3xy2 + 4y
Add the following expressions:
p2 – q + r, q2 – r + p and r2 – p + q
Add the following expressions:
uv – vw, vw – wu and wu – uv
What should be added to x3 + 3x2y + 3xy2 + y3 to get x3 + y3?
