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प्रश्न
Subtract:
\[x^2 y - \frac{4}{5}x y^2 + \frac{4}{3}xy \text { from } \frac{2}{3} x^2 y + \frac{3}{2}x y^2 - \frac{1}{3}xy\]
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उत्तर
\[ \left( \frac{2}{3} x^2 y + \frac{3}{2}x y^2 - \frac{1}{3}xy \right) - \left( x^2 y - \frac{4}{5}x y^2 + \frac{4}{3}xy \right)\]
\[ = \frac{2}{3} x^2 y + \frac{3}{2}x y^2 - \frac{1}{3}xy - x^2 y + \frac{4}{5}x y^2 - \frac{4}{3}xy\]
\[ = \frac{2}{3} x^2 y - x^2 y + \frac{3}{2}x y^2 + \frac{4}{5}x y^2 - \frac{1}{3}xy - \frac{4}{3}xy (\text { Collecting like terms })\]
\[ = - \frac{1}{3} x^2 y + \frac{23}{10}x y^2 - \frac{5}{3}xy (\text { Combining like terms })\]
संबंधित प्रश्न
Add the following:
a − b + ab, b − c + bc, c − a + ac
Simplify combining like terms: (3y2 + 5y - 4) - (8y - y2 - 4)
Add: ab - 4a, 4b - ab, 4a - 4b
Subtract:
\[\frac{2}{3} y^3 - \frac{2}{7} y^2 - 5 \text { from }\frac{1}{3} y^3 + \frac{5}{7} y^2 + y - 2\]
Add:
−3y2 + 10y − 16; 7y2 + 8
Solve:
(6a − 5b − 8c) + (15b + 2a − 5c)
Find the expression to be added with 5a – 3b – 2c to get a – 4b – 2c?
a(b + c) = a × ____ + a × _____.
Sum of x and y is x + y.
How much is y4 – 12y2 + y + 14 greater than 17y3 + 34y2 – 51y + 68?
