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प्रश्न
Subtract:
\[x^2 y - \frac{4}{5}x y^2 + \frac{4}{3}xy \text { from } \frac{2}{3} x^2 y + \frac{3}{2}x y^2 - \frac{1}{3}xy\]
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उत्तर
\[ \left( \frac{2}{3} x^2 y + \frac{3}{2}x y^2 - \frac{1}{3}xy \right) - \left( x^2 y - \frac{4}{5}x y^2 + \frac{4}{3}xy \right)\]
\[ = \frac{2}{3} x^2 y + \frac{3}{2}x y^2 - \frac{1}{3}xy - x^2 y + \frac{4}{5}x y^2 - \frac{4}{3}xy\]
\[ = \frac{2}{3} x^2 y - x^2 y + \frac{3}{2}x y^2 + \frac{4}{5}x y^2 - \frac{1}{3}xy - \frac{4}{3}xy (\text { Collecting like terms })\]
\[ = - \frac{1}{3} x^2 y + \frac{23}{10}x y^2 - \frac{5}{3}xy (\text { Combining like terms })\]
संबंधित प्रश्न
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− 5xy from 12xy
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2a2 from − 7a2
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\[\frac{3}{2}x - \frac{5}{4}y - \frac{7}{2}z \text { from }\frac{2}{3}x + \frac{3}{2}y - \frac{4}{3}z\]
Add:
17a2b2 + 16c; 28c − 28a2b2
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What should be added to 3pq + 5p2q2 + p3 to get p3 + 2p2q2 + 4pq?
