Advertisements
Advertisements
प्रश्न
Multiply: \[\left( - \frac{a}{7} + \frac{a^2}{9} \right)by\left( \frac{b}{2} - \frac{b^2}{3} \right)\].
Advertisements
उत्तर
To multiply, we will use distributive law as follows:
\[\left( - \frac{a}{7} + \frac{a^2}{9} \right)\left( \frac{b}{2} - \frac{b^2}{3} \right)\]
\[ = \left( - \frac{a}{7} \right)\left( \frac{b}{2} - \frac{b^2}{3} \right) + \left( \frac{a^2}{9} \right)\left( \frac{b}{2} - \frac{b^2}{3} \right)\]
\[ = \left( - \frac{ab}{14} + \frac{a b^2}{21} \right) + \left( \frac{a^2 b}{18} - \frac{a^2 b^2}{27} \right)\]
\[ = - \frac{ab}{14} + \frac{a b^2}{21} + \frac{a^2 b}{18} - \frac{a^2 b^2}{27}\]
Thus, the answer is \[- \frac{ab}{14} + \frac{a b^2}{21} + \frac{a^2 b}{18} - \frac{a^2 b^2}{27}\].
APPEARS IN
संबंधित प्रश्न
Find each of the following product:
\[\frac{1}{4}xy \times \frac{2}{3} x^2 y z^2\]
Find each of the following product: \[\left( \frac{7}{9}a b^2 \right) \times \left( \frac{15}{7}a c^2 b \right) \times \left( - \frac{3}{5} a^2 c \right)\]
Simplify: x(x + 4) + 3x(2x2 − 1) + 4x2 + 4
Simplify: a(b − c) − b(c − a) − c(a − b)
Multiply:
(3x2 + y2) by (2x2 + 3y2)
Multiply:
(0.8a − 0.5b) by (1.5a − 3b)
Simplify:
(5x − 3)(x + 2) − (2x + 5)(4x − 3)
Simplify:
(x3 − 2x2 + 3x − 4) (x −1) − (2x − 3)(x2 − x + 1)
Show that: (a − b)(a + b) + (b − c)(b + c) + (c − a)( c + a) = 0
Which formula represents multiplication of powers with the same base?
