Advertisements
Advertisements
प्रश्न
Multiply: \[\left( - \frac{a}{7} + \frac{a^2}{9} \right)by\left( \frac{b}{2} - \frac{b^2}{3} \right)\].
Advertisements
उत्तर
To multiply, we will use distributive law as follows:
\[\left( - \frac{a}{7} + \frac{a^2}{9} \right)\left( \frac{b}{2} - \frac{b^2}{3} \right)\]
\[ = \left( - \frac{a}{7} \right)\left( \frac{b}{2} - \frac{b^2}{3} \right) + \left( \frac{a^2}{9} \right)\left( \frac{b}{2} - \frac{b^2}{3} \right)\]
\[ = \left( - \frac{ab}{14} + \frac{a b^2}{21} \right) + \left( \frac{a^2 b}{18} - \frac{a^2 b^2}{27} \right)\]
\[ = - \frac{ab}{14} + \frac{a b^2}{21} + \frac{a^2 b}{18} - \frac{a^2 b^2}{27}\]
Thus, the answer is \[- \frac{ab}{14} + \frac{a b^2}{21} + \frac{a^2 b}{18} - \frac{a^2 b^2}{27}\].
संबंधित प्रश्न
Simplify: x3y(x2 − 2x) + 2xy(x3 − x4)
Multiply:
(x6 − y6) by (x2 + y2)
Multiply:
(0.8a − 0.5b) by (1.5a − 3b)
Multiply:
(2x2y2 − 5xy2) by (x2 − y2)
Multiply:
(2x2 − 1) by (4x3 + 5x2)
(2xy + 3y2) (3y2 − 2)
Find the following product and verify the result for x = − 1, y = − 2:
(x2y − 1) (3 − 2x2y)
Show that: \[\left( \frac{4m}{3} - \frac{3n}{4} \right)^2 + 2mn = \frac{16 m^2}{9} + \frac{9 n^2}{16}\]
Show that: (a − b)(a + b) + (b − c)(b + c) + (c − a)( c + a) = 0
What is the product of (x + 3) and (x − 5)?
