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प्रश्न
Subtract the sum of 12ab – 10b2 – 18a2 and 9ab + 12b2 + 14a2 from the sum of ab + 2b2 and 3b2 – a2.
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उत्तर
Sum of 12ab – 10b2 – 18a2 and 9ab + 12b2 + 14a2
= 12ab – 10b2 – 18a2 + 9ab + 12b2 + 14a2
On combining the like terms,
= 12ab + 9ab – 10b2 + 12b2 – 18a2 + 14a2
= 21ab + 2b2 – 4a2
Sum of ab + 2b2 and 3b2 – a2
= ab + 2b2 + 3b2 – a2
= ab + 5b2 – a2
Now, subtracting 21ab + 2b2 – 4a2 from ab + 5b2 – a2, we get
= (ab + 5b2 – a2) – (21ab + 2b2 – 4a2)
= ab + 5b2 – a2 – 21ab – 2b2 + 4a2
On combining the like terms,
= ab – 21ab + 5b2 – 2b2 – a2 + 4a2
= –20ab + 3b2 + 3a2
= 3a2 + 3b2 – 20ab
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