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Question
On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. Which stone would reach the ground first and why?
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Solution
A stone is thrown from a height in a direction parallel to the earth’s surface, i.e., the stone is given initial velocity in the horizontal direction.
For the vertical motion of the stone, u = 0, a – g and s = h
Using s = `"ut" + 1/2 "at"^2`
we get t = `sqrt((2"h")/"g")`
Similarly, for the second stone, vertical motion is the same as that of the first. So, both the stones would reach the ground simultaneously.
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