Advertisements
Advertisements
Question
On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. Which stone would reach the ground first and why?
Advertisements
Solution
A stone is thrown from a height in a direction parallel to the earth’s surface, i.e., the stone is given initial velocity in the horizontal direction.
For the vertical motion of the stone, u = 0, a – g and s = h
Using s = `"ut" + 1/2 "at"^2`
we get t = `sqrt((2"h")/"g")`
Similarly, for the second stone, vertical motion is the same as that of the first. So, both the stones would reach the ground simultaneously.
APPEARS IN
RELATED QUESTIONS
What is the value of gravitational constant G (i) on the earth, and (ii) on the moon ?
The CGS unit of G is dyne.cm2/g2.
The value of G varies from place to place.
As we go above the earth's surface, value of g increases.
Write scientific reason.
The value of g at the centre of the earth is zero.
The radius of the orbit of a geostationary satellite is (mean radius of the earth R, angular velocity about an axis in ω and acceleration due to gravity on earth's surface is (g) ______.
Write if the following statement is correct or wrong.
The value of g is the same everywhere on the surface of the earth.
A body is thrown from the surface of the earth with velocity 'u' m/s. The maximum height in m above the surface of the earth upto which it will reach is ______.
(R = radius of earth, g = acceleration due to gravity)
The acceleration due to gravity on the earth of radius Re is ge, and that on moon of radius Rm, is gm. The ratio of the masses of the earth and moon is given by ______.
Which formula correctly represents the acceleration due to gravity at Earth's surface?
