Advertisements
Advertisements
Question
Is the acceleration due to gravity of earth ‘g’ a constant ? Discuss.
Advertisements
Solution
No, the value of acceleration due to gravity (g) is not constant at all the places on the surface of the earth. Since the radius of the earth is minimum at the poles and maximum at the equator, the value of g is maximum at the poles and minimum at the equator. As we go up from the surface of the earth, the distance from the centre of the earth increases and hence the value of g decreases. The value of g also decreases as we go down inside the earth.
APPEARS IN
RELATED QUESTIONS
If the value of g suddenly becomes twice its value, it will become two times more difficult to pull a heavy object along the floor. Why?
Why does the velocity of a stone thrown vertically upwards decreases?
The value of gravitational acceleration (g) is ________ at the equator.
The CGS unit of G is dyne.cm2/g2.
The mass of the moon is `1/81` of the mass of the earth. Its diameter is `1/3.7` of that of the earth. If acceleration due to gravity on the surface of the earth is 9.8 m/s2, then the acceleration due to gravity on the surface of the moon.
The depth 'd' below the surface of the earth at which acceleration due to gravity becomes `(g/n)` is ______.
R = radius of the earth, 'g' = acceleration due to gravity, n = integer
In the relation F = `"G M" "m"//"d"^2`, the quantity G
On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. Which stone would reach the ground first and why?
The difference in the acceleration due to gravity at the pole and equator is ______.
(g = acceleration due to gravity, R = radius of the earth; θ = latitude, ω = angular velocity, cos0° = 1, cos90° = 0)
When equating the gravitational force with Newton's Second Law force to derive g, which term cancels out?
