Advertisements
Advertisements
Question
In the relation F = `"G M" "m"//"d"^2`, the quantity G
Options
depends on the value of g at the place of observation
is used only when the earth is one of the two masses
is greatest at the surface of the earth
is the universal constant of nature
Advertisements
Solution
is the universal constant of nature
Explanation:
In the relation F = `"G" "Mm"/"d"^2` the quantity G is the universal constant of nature.
APPEARS IN
RELATED QUESTIONS
Is the acceleration due to gravity of earth ‘g’ a constant ? Discuss.
The radius of planet A is half the radius of planet B. If the mass of A is MA, what must be the mass of B so that the value of g on B is half that of its value on A?
Write scientific reasons.
The value of g at the centre of the earth is zero.
______ is used to change the speed of the car.
The mass of the moon is `1/81` of the mass of the earth. Its diameter is `1/3.7` of that of the earth. If acceleration due to gravity on the surface of the earth is 9.8 m/s2, then the acceleration due to gravity on the surface of the moon.
A central particle M is surrounded by a square array of other particles, separated by either distanced or distance d/2 along the perimeter o the square. The magnitude of the gravitational force on the central particle due to the other particles is ______.

The depth 'd' at which the value of acceleration due to gravity becomes `"I"/"n"` times the value at the earth's surface is ______. (R = radius of earth)
If the change in the value of g at the height h above the surface of the earth is the same as at a depth x below it, then ______.
(both x and h being much smaller than the radius of the earth)
A uniform ring of mass M and radius r is placed directly above a uniform sphere of mass 8M and of same radius R. The centre of the ring is at a distance of d = `sqrt3`R from the centre of the sphere. The gravitational attraction between the sphere and the ring is ______.
The value of acceleration due to gravity at Earth’s surface is 9.8 ms−2. The altitude above its surface at which the acceleration due to gravity decreases to 4.9 ms−2, is close to ______.
(Radius of earth = 6.4 × 106 m)
