Question

On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. Which stone would reach the ground first and why?

Answer 1

A stone is thrown from a height in a direction parallel to the earth’s surface, i.e., the stone is given initial velocity in the horizontal direction.
For the vertical motion of the stone, u = 0, a – g and s = h

Using s = `"ut" + 1/2 "at"^2`

we get t = `sqrt((2"h")/"g")`

Similarly, for the second stone, vertical motion is the same as that of the first. So, both the stones would reach the ground simultaneously.