Advertisements
Advertisements
प्रश्न
Suppose the gravity of the earth suddenly becomes zero, then in which direction will the moon begin to move if no other celestial body affects it?
Advertisements
उत्तर
The circular motion of the moon around the earth is due to the centripetal force provided by the gravitational force of the earth. Therefore,
when the gravity of the earth suddenly becomes zero, the moon will begin to move in a straight line in the direction in which it was moving at that instant. That is the moon will move along the tangent to the circular orbit at that instant.
APPEARS IN
संबंधित प्रश्न
If the value of g suddenly becomes twice its value, it will become two times more difficult to pull a heavy object along the floor. Why?
The CGS unit of G is dyne.cm2/g2.
The mass of a body on the surface of the earth is 10 kg. The mass of the same body on the surface on the moon is `"g"_"m" = 1/6 "g"_"e"`, where gm, ge acceleration due to gravity on the surface of the moon and the earth respectively.
The acceleration due to gravity on a planet is 1.96 m/s2. If it is safe to jump from a height of 3 m on tbe earth, the corresponding height on the planet will be ____________.
The acceleration due to gravity on moon is `(1/6)^"th"` times the acceleration due to gravity on earth. If the ratio of the density of earth 'ρe' to the density of moon 'ρm' is `5/3`, then the radius of moon 'Rm' in terms of the radius of earth 'Re' is ______.
The radius of the orbit of a geostationary satellite is (mean radius of the earth R, angular velocity about an axis in ω and acceleration due to gravity on earth's surface is (g) ______.
A central particle M is surrounded by a square array of other particles, separated by either distanced or distance d/2 along the perimeter o the square. The magnitude of the gravitational force on the central particle due to the other particles is ______.
A body is thrown from the surface of the earth with velocity 'u' m/s. The maximum height in m above the surface of the earth upto which it will reach is ______.
(R = radius of earth, g = acceleration due to gravity)
The depth 'd' at which the value of acceleration due to gravity becomes `"I"/"n"` times the value at the earth's surface is ______. (R = radius of earth)
Which formula correctly represents the acceleration due to gravity at Earth's surface?
