Advertisements
Advertisements
Question
Numerical Problem.
What is the heat in joules required to raise the temperature of 25 grams of water from 0°C to 100°C? What is the heat in Calories? (Specific heat of water = `(4.18"J")/("g"°"C")`
Advertisements
Solution
Given m = 25 g, ∆T = (100 – 0) = 100°C
Or in terms of Kelvin (373.15 – 273.15) = 100K,
C = `(4.18"J")/("g"°"C")`
Heat energy required, Q = m × C × ∆T = 25 × 4.18 × 100 = 10450 J
APPEARS IN
RELATED QUESTIONS
Calculate the mass of ice required to lower the temperature of 300 g of water 40°C to water at 0°C.
(Specific latent heat of ice = 336 J/g, the Specific heat capacity of water = 4.2J/g°C)
How much heat energy is released when 5.0 g of water at 20℃ changes into ice at 0℃? Take specific heat capacity of water = 4.2 J g-1 K-1, Specific latent heat of fusion of ice = 336 J g-1.
The ratio of specific heat capacity to molar heat capacity of a body _____________ .
What is the unit of heat capacity in CGS system?
650 J of heat is required to raise the temp. of 0.25 kg of lead from 15°C to 35°C. Calculate the Sp. heat capacity of lead.
The temperature of a lead piece of mass 400 g rises from 20°C to 50°C when 1560 J of heat is supplied to it. Calculate: Heat capacity of lead piece.
Solve the following problem.
What is the specific heat of metal if 50 cal of heat is needed to raise 6 kg of the metal from 20°C to 62 °C?
The SI unit of specific heat is _______.
Numerical Problem.
What could be the final temperature of a mixture of 100 g of water at 90 °C and 600g of water at 20°C.
