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Ms. Chitra Opened a Saving Bank Account with Sbi on 05.04.2007 with a Cheque Deposit of Rs 11,000/.

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Question

Ms. Chitra opened a saving bank account with SBI on 05.04.2007 with a cheque deposit of Rs 11,000/.Subsequently, she took out Rs 3,200/- on 12.05.2007; deposited a cheque of Rs. 8,800/- on 03.06.2007 and paid Rs 2,000/- by cheque on 18.06.2007.

If the rate of simple interest was 5% pa compounded at the end of March and September, find her balance on 1.04.2008

Sum
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Solution

If the rate of simple interest was 5°/o pa compounded at the end of March and September, find her balance on 1.04.2008 According to the entries in passbook, the minimum balance tor ditterent months are as follows: 

Months Minimum balance between 10th day and the last day  Minimum balance in nearest multiple of 10 
2007,April 11000 11000
May 7800 7800
June 14600 14600
July 14600 14600
August 14600 14600
September 14600 14600
October 14600 + 322 = 14922 14920
November 14922 14920
December 14922 14920
2008,January 14922 14920
February 14922 14920
March 14922 14920

Total principal at the end of September 2007

=Rs 11000 + 7800 + 14600 x 4

=Rs 77200

Therefore interest at the end of sep. 2007

= `(77200 xx 5 xx 1)/(100 xx 12) = 321.66`

Thus interest earned is Rs 322 

Again, principal at the end of March, 2008 = 14920x6 = 89520 

Therefore interest at the end of Mar. 2008

= `(89520 xx 5 xx 1)/(100 xx 12) = 373`

Hence, Account balance as on 01.04.2008 is

= Rs 14920 +Rs 373 

=Rs 15293

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Chapter 2: Banking - Exercise 3.1 [Page 45]

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Frank Mathematics Part 2 [English] Class 10 ICSE
Chapter 2 Banking
Exercise 3.1 | Q 2.2 | Page 45

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