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Question
Ms. Chitra opened a saving bank account with SBI on 05.04.2007 with a cheque deposit of Rs 11,000/.Subsequently, she took out Rs 3,200/- on 12.05.2007; deposited a cheque of Rs. 8,800/- on 03.06.2007 and paid Rs 2,000/- by cheque on 18.06.2007.
If the rate of simple interest was 5% pa compounded at the end of March and September, find her balance on 1.04.2008
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Solution
If the rate of simple interest was 5°/o pa compounded at the end of March and September, find her balance on 1.04.2008 According to the entries in passbook, the minimum balance tor ditterent months are as follows:
| Months | Minimum balance between 10th day and the last day | Minimum balance in nearest multiple of 10 |
| 2007,April | 11000 | 11000 |
| May | 7800 | 7800 |
| June | 14600 | 14600 |
| July | 14600 | 14600 |
| August | 14600 | 14600 |
| September | 14600 | 14600 |
| October | 14600 + 322 = 14922 | 14920 |
| November | 14922 | 14920 |
| December | 14922 | 14920 |
| 2008,January | 14922 | 14920 |
| February | 14922 | 14920 |
| March | 14922 | 14920 |
Total principal at the end of September 2007
=Rs 11000 + 7800 + 14600 x 4
=Rs 77200
Therefore interest at the end of sep. 2007
= `(77200 xx 5 xx 1)/(100 xx 12) = 321.66`
Thus interest earned is Rs 322
Again, principal at the end of March, 2008 = 14920x6 = 89520
Therefore interest at the end of Mar. 2008
= `(89520 xx 5 xx 1)/(100 xx 12) = 373`
Hence, Account balance as on 01.04.2008 is
= Rs 14920 +Rs 373
=Rs 15293
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