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Mohan has a recurring deposit account in a bank for 2 years at 6% p.a. simple interest. If he gets Rs. 1200 as interest at the time of maturity, find: the monthly instalment. the amount of maturity.

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Questions

Mohan has a recurring deposit account in a bank for 2 years at 6% p.a. simple interest. If he gets Rs. 1200 as interest at the time of maturity, find:

  1. the monthly instalment.
  2. the amount of maturity.

Mohan has a recurring deposit account in a bank for 2 years at 6% p.a. simple interest. If he gets Rs. 1200 as interest at the time of maturity, find:

  1. the monthly instalment.
  2. the amount of maturity.
  3. If Mohan decreases his monthly instalment by 20%, how much less interest will he get at the same rate of interest and for the same time?
Sum
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Solution

Interest = Rs. 1200

Period (n) = 2 years = 24 months

Rate (r) = 6% p.a.

i. Let monthly deposit = ₹ P p.m.

∴ Interest = `(P xx n(n + 1))/(2 xx 12) xx r/(100)`

`1200 = (P xx 24 xx 25)/(24) xx (6)/(100)`

`\implies 1200 = (6)/(4)p`

∴ `P = (1200 xx 4)/(6) = 800`

∴ Monthly deposit = ₹ 800

ii. Maturity value = P × n + Interest

= ₹ 800 × 24 + ₹ 1,200

= ₹ 19,200 + ₹ 1,200

= ₹ 20,400

iii. Interest when monthly instalment is decreased by 20%

Original monthly instalment = ₹ 800

Decrease = 20% of ₹ 800

= `20/100 xx ₹ 800`

= ₹ 160

New monthly instalment = ₹ 800 − ₹ 160

= ₹ 640

Since the rate and period remain the same, interest is directly proportional to the monthly instalment.

New Interest = `₹ 1,200 xx 640/800`

= ₹ 960

Therefore, less interest received = ₹ 1,200 − ₹ 960

= ₹ 240

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Notes

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Chapter 2: Banking (Recurring Deposit Account) - EXERCISE 2 [Page 21]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 2 Banking (Recurring Deposit Account)
EXERCISE 2 | Q 8. | Page 21

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Fill in the blanks in the table.

Principal Rate of interest (p.c.p.a.) Time Interest Amount
...... 6% 4 years 1200 ......

Fill in the blanks in the table.

Principal Rate of interest (p.c.p.a.) Time Interest Amount
8000 5% ...... 800 ......

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