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Mr. X goes to office by Auto, Car, and train. The probabilities him travelling by these modes are 27,37,27 respectively. The chances of him being late to the office are 12,14,14 respectively - Mathematics and Statistics

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Question

(Activity):

Mr. X goes to office by Auto, Car, and train. The probabilities him travelling by these modes are `2/7, 3/7, 2/7` respectively. The chances of him being late to the office are `1/2, 1/4, 1/4` respectively by Auto, Car, and train. On one particular day, he was late to the office. Find the probability that he travelled by car.

Solution: Let A, C and T be the events that Mr. X goes to office by Auto, Car and Train respectively. Let L be event that he is late.

Given that P(A) = `square`, P(C) = `square`

P(T) = `square`

P(L/A) = `1/2`, P(L/C) = `square` P(L/T) = `1/4`

P(L) = P(A ∩ L) + P(C ∩ L) + P(T ∩ L)

`="P"("A")*"P"("L"//"A") + "P"("C")*"P"("L"//"C") + "P"("T")*"P"("L"//"T")`

`= square * square + square * square + square * square`

`= square + square + square`

`= square`

`"P"("C"//"L") = ("P"("L" ∩ "C"))/("P"("L"))`

= `("P"("C") * "P"("L"//"C"))/("P"("L"))`

`= (square * square)/square`

`= square`

Sum
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Solution

Let A, C, and T be the events that Mr. X goes to office by Auto, Car, and Train respectively. Let L be event that he is late.

Given that P(A) = `underline(2/7)`, P(C) = `underline(3/7)`, P(T) = `underline(2/7)`

`"P"("L"//"A") = 1/2, "P"("L"//"C") = underline(1/4), "P"("L"//"T") = 1/4` 

P(L) = P(A ∩ L) + P(C ∩ L) + P(T ∩ L)

`="P"("A")*"P"("L"//"A") + "P"("C")*"P"("L"//"C") + "P"("T")*"P"("L"//"T")`

= `underline(2/7) xx underline(1/2) + underline(3/7) xx underline(1/4) + underline(2/7) xx underline(1/4)`

= `underline(1/7) + underline(3/28) + underline(2/28)`

`= underline(9/28)`

`"P"("C"//"L") = ("P"("L" ∩ "C"))/("P"("L"))`

= `("P"("C") * "P"("L"//"C"))/("P"("L"))`

= `(underline(3/7) xx underline(1/4))/(underline(9/28)`

= `underline(1/3)`

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Chapter 9: Probability - Exercise 9.4 [Page 210]

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