Question

Mr. Kasam runs a small business of making earthen pots. He makes certain number of pots on daily basis. Production cost of each pot is Rs 40 more than 10 times total number of pots, he makes in one day. If production cost of all pots per day is Rs 600, find production cost of one pot and number of pots he makes per day.

 

Answer 1

Let the number of pots Mr. Kasam makes in one day be x. 
Production cost of each pot is Rs 40 more than 10 times total number of pots, he makes in one day = 10x + 40
Production cost of all pots per day is Rs 600
(10x + 40)x = 600 

\[10 x^2 + 40x = 600\]
\[ \Rightarrow x^2 + 4x - 60 = 0\]
\[ \Rightarrow x^2 + 10x - 6x - 60 = 0\]
\[ \Rightarrow x\left( x + 10 \right) - 6\left( x + 10 \right) = 0\]
\[ \Rightarrow \left( x - 6 \right)\left( x + 10 \right) = 0\]
\[ \Rightarrow x = 6, - 10\] 

But the number of pots cannot be negative so,  

\[x \neq - 10\]
\[ \Rightarrow x = 6\]  

Production cost of 1 pot = \[10 \times 6 + 40 = 60 + 40 = Rs 100\]