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Maharashtra State BoardSSC (English Medium) 10th Standard

Pratik takes 8 hours to travel 36 km downstream and return to the same spot. The speed of boat in still water is 12 km. per hour. Find the speed of water current.

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Question

Pratik takes 8 hours to travel 36 km downstream and return to the same spot. The speed of boat in still water is 12 km. per hour. Find the speed of water current. 

Sum
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Solution

Let the speed of water current = x km/h

Speed of boat in still water = 12 km/h

Speed upstream =  (12 − x) km/h

Speed downstream = (12 + x) km/h

Distance travelled = 36 km downstream and 36 km upstream

Total time taken by Pratik = 8 hrs

Speed = `"Distance"/"Time"`

∵ Time = `"Distance"/"Speed"`

Time taken to travel 36 km downstream + time taken to travel 36 km Upstream = 8 hrs

⇒ `36/(12 + x) + 36/(12 - x)` = 8

⇒ `36[1/(12 + x) + 1/(12 - x)]` = 8

⇒ `9[((12 - x) + (12 + x))/((12 + x)(12 - x))]` = 2

⇒ `9[(12 - x + 12 + x)/(144 - x^2)]` = 2

⇒ `9 xx 24/(144 - x^2)` = 2

⇒ 9 × 24 = 2(144 − x2)

⇒ `(9 xx 24)/2 = 144 - x^2`

⇒ 9 × 12 = 144 − x2

⇒ 108 = 144 − x2

⇒ x2 = 144 − 108

⇒ 9 × 24 = 2(144 −x2)

⇒ 9 × 12 = 144 − x2

⇒ 144 − 108 = −x2

⇒ x2 = 36

⇒ x = ±6

But speed ≠ negative.

So, x = 6 km/h

Hence, the speed of the water current is 6 km/h.

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Chapter 2: Quadratic Equations - Practice Set 2.6 [Page 52]

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Balbharati Algebra Mathematics 1 [English] Standard 10 Maharashtra State Board
Chapter 2 Quadratic Equations
Practice Set 2.6 | Q 7 | Page 52
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