English
Maharashtra State BoardSSC (English Medium) 10th Standard

Pratik takes 8 hours to travel 36 km downstream and return to the same spot. The speed of boat in still water is 12 km. per hour. Find the speed of water current. - Algebra Mathematics 1

Advertisements
Advertisements

Question

Pratik takes 8 hours to travel 36 km downstream and return to the same spot. The speed of boat in still water is 12 km. per hour. Find the speed of water current. 

Sum
Advertisements

Solution

Let the speed of water current = x km/h

Speed of boat in still water = 12 km/h

Speed upstream =  (12 − x) km/h

Speed downstream = (12 + x) km/h

Distance travelled = 36 km downstream and 36 km upstream 

Total time taken by Pratik = 8 hrs

`"Speed" = "Distance"/"Time"`

∵ `"Time" = "Distance"/"Speed"`

Time taken to travel 36 km downstream + time taken to travel 36 km Upstream = 8hrs

`⇒ 36/(12 + x) + 36/(12 - x) = 8`

`⇒ 36[1/(12 + x) + 1/(12 - x)] = 8`

`⇒ 9[((12 - x) + (12 + x))/((12 + x)(12 - x))] = 2`

`⇒ 9[(12 - x + 12 + x)/(144 - x^2)] = 2`

`⇒ 9 × 24/(144 - x^2) = 2`

`⇒ 9 × 24 = 2(144 - x^2) `

`⇒ (9 × 24)/2 = 144 - x^2 `

`⇒ 9 × 12 = 144 - x^2 `

`⇒ 108 = 144 - x^2 `

`⇒ x^2 = 144 - 108`

`=> 9 xx 24 = 2 (144 - x^2)`

`=> 9 xx 12 = 144 - x^2`

`=> 144 - 108 = - x^2`

`=> x^2 = 36`

`=> x = +- 6` , but speed ≠ negative

so , x = 6 km/h

Hence, speed of water current is 6 km/h

shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Quadratic Equations - Practice Set 2.6 [Page 52]

APPEARS IN

Balbharati Algebra (Mathematics 1) [English] Standard 10 Maharashtra State Board
Chapter 2 Quadratic Equations
Practice Set 2.6 | Q 7 | Page 52
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×