Advertisements
Advertisements
Question
Match the following:
| Shapes | Perimeter |
(A) ![]() |
(i) 10 |
(B) ![]() |
(ii) 18 |
(C) ![]() |
(iii) 20 |
(D) ![]() |
(iv) 25 |
Advertisements
Solution
| Shapes | Perimeter |
(A) ![]() |
(iii) 20 |
(B) ![]() |
(iii) 20 |
(C) ![]() |
(ii) 18 |
(D) ![]() |
(i) 10 |
Explanation:
(A) We know that,
Perimeter of a rectangle = 2 × (Length + Breadth)
Here, length = 6 and breadth = 4
∴ Perimeter of a rectangle = 2 × (6 + 4)
= 2 × 10
= 20
(B) Here, side = 5
∴ Perimeter of a square = 4 × Side ...[∵ In square all sides are equal]
= 4 × 5
= 20
(C) Here, side = 6
∴ Perimeter of an equilateral triangle = 3 × Length of a side
= 3 × 6
= 18
(D) Given sides are 4, 4 and 2.
∴ Perimeter of an isosceles triangle = Sum of all sides
= 4 + 4 + 2
= 10
APPEARS IN
RELATED QUESTIONS
Find the perimeter of the following figure:

The area of a rectangular shaped photo is 820 sq.cm. and its width is 20 cm. What is its length? Also find its perimeter
Perimeter of a regular octagon of side 6 cm is 36 cm.
To find the cost of painting a wall we need to find the perimeter of the wall.
To find the cost of a frame of a picture, we need to find the perimeter of the picture.
What is the length of outer boundary of the park shown in the following figure? What will be the total cost of fencing it at the rate of Rs 20 per metre? There is a rectangular flower bed in the center of the park. Find the cost of manuring the flower bed at the rate of Rs 50 per square metre.

Length of a rectangular field is 6 times its breadth. If the length of the field is 120 cm, find the breadth and perimeter of the field.
Find the perimeter of the following figure:

Find the perimeter of the following shape:
An equilateral triangle of side 9 cm.
Out of two figures if one has larger area, then its perimeter need not to be larger than the other figure.




