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Question
Match the shapes (each sides measures 2 cm) in column I with the corresponding perimeters in column II:
| Column I | Column II |
(A) ![]() |
(i) 16 cm |
(B) ![]() |
(ii) 20 cm |
(C) ![]() |
(iii) 24 cm |
(D) ![]() |
(iv) 28 cm |
| (v) 32 cm |
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Solution
| Column I | Column II |
(A) ![]() |
(iv) 28 cm |
(B) ![]() |
(i) 16 cm |
(C) ![]() |
(ii) 20 cm |
(D) ![]() |
(iii) 24 cm |
Explanation:
(A) Perimeter of figure = Sum of all sides
= AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LM + MN + NA
= 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2
= 28 cm
(B) Perimeter of figure = Sum of all sides
= AB + BC + CD + DE + EF + FG + GH + HA
= 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2
= 16 cm
(C) Perimeter of figure = Sum of all sides
= AB + BC + CD + DE + EF + FG + GH + HI + U + JA
= 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2
= 20 cm
(D) Perimeter of figure = Sum of all sides
= AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LA
= 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2
= 24 cm
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