Advertisements
Advertisements
Question
Let A = {1, 2, 3, 7} and B = {3, 0, –1, 7}, the following is relation from A to B?
R4 = {(7, –1), (0, 3), (3, 3), (0, 7)}
Advertisements
Solution
A = {1, 2, 3, 7} B = {3, 0, –1, 7}
A × B = {1, 2, 3} × {3, 0, –1, 7}
A × B = {(1, 3) (1, 0) (1, –1) (1, 7) (2, 3) (2, 0) (2, –1) (2, 7) (3, 3) (3, 0) (3, –1) (3, 7) (7, 3) (7, 0) (7, –1) (7, 7)}
R4 = {(7, –1), (0, 3), (3, 3), (0, 7)}
It is not a relation, there is no element of (0, 3) and (0, 7) in A × B
APPEARS IN
RELATED QUESTIONS
Define a relation R on the set N of natural numbers by R = {(x, y): y = x + 5, x is a natural number less than 4; x, y ∈ N}. Depict this relationship using roster form. Write down the domain and the range.
Let A = [1, 2] and B = [3, 4]. Find the total number of relation from A into B.
Let A = (x, y, z) and B = (a, b). Find the total number of relations from A into B.
Let R be a relation from N to N defined by R = {(a, b) : a, b ∈ N and a = b2}. Is the statement true?
(a, b) ∈ R and (b, c) ∈ R implies (a, c) ∈ R
Justify your answer in case.
If n(A) = 3, n(B) = 4, then write n(A × A × B).
Let R be a relation on N defined by x + 2y = 8. The domain of R is
Let A = {1, 2, 3, 4), B = {4, 5, 6}, C = {5, 6}. Verify, A × (B ∪ C) = (A × B) ∪ (A × C)
Is the given relation a function? Give reasons for your answer.
s = {(n, n2) | n is a positive integer}
Let S = {x ∈ R : x ≥ 0 and `2|sqrt(x) - 3| + sqrt(x)(sqrt(x) - 6) + 6 = 0}`. Then S ______.
Which statement defines a relation from set \(A\) to set \(B\)?
