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Question
Is the following sugar, D-sugar or L-sugar?
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Solution
L-sugar
\[\begin{array}{cc}
\phantom{.....}\ce{^1CHO}\\
\phantom{...}|\\
\ce{HO - ^2C - H}\\
\phantom{...}|\\
\phantom{........}\ce{\underset{L-Glyceraldehyde}{^3CH2OH}}
\end{array}\]
Because the H and OH on C4 carbon is in the same configuration as the H and OH on C2
carbon in L-Glyceraldehyde.
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