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Question
Integrate the following with respect to x :
`1/(x log x log (log x))`
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Solution
`int 1/(x log x log (log x)) * "d"x`
Put `log(log x)` = u
`1/log x xx 1/x xx "d"x` = du
`1/(xlogx) "d"x` = du
`int 1/(log(log x)) * 1/(xlogx) "d"x = int 1/"u" * "du" + "c"`
= `log|"u"| + "c"`
`int 1/(log(log x)) * 1/(xlogx) "d"x = log |log(log x)| + "c"`
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