Advertisements
Advertisements
प्रश्न
Integrate the following with respect to x :
`1/(x log x log (log x))`
Advertisements
उत्तर
`int 1/(x log x log (log x)) * "d"x`
Put `log(log x)` = u
`1/log x xx 1/x xx "d"x` = du
`1/(xlogx) "d"x` = du
`int 1/(log(log x)) * 1/(xlogx) "d"x = int 1/"u" * "du" + "c"`
= `log|"u"| + "c"`
`int 1/(log(log x)) * 1/(xlogx) "d"x = log |log(log x)| + "c"`
APPEARS IN
संबंधित प्रश्न
Evaluate : `int (1+logx)/(x(2+logx)(3+logx))dx`
Integrate the following functions with respect to x :
cot2x + tan2x
Integrate the following functions with respect to x :
`(sin4x)/sinx`
Integrate the following functions with respect to x :
cos 3x cos 2x
Integrate the following functions with respect to x :
sin2 5x
Integrate the following functions with respect to x :
`(3x - 9)/((x - 1)(x + 2)(x^2 + 1))`
Integrate the following with respect to x :
`("e"^x - "e"^-x)/("e"^x + "e"^-x)`
Integrate the following with respect to x :
`(sin sqrt(x))/sqrt(x)`
Integrate the following with respect to x :
`cosx/(cos(x - "a"))`
Integrate the following with respect to x:
25xe–5x
Integrate the following with respect to x:
x2 cos x
Integrate the following with respect to x:
`tan^-1 ((8x)/(1 - 16x^2))`
Integrate the following with respect to x:
`"e"^x sec x(1 + tan x)`
Integrate the following with respect to x:
`"e"^(tan^-1 x) ((1 + x + x^2)/(1 + x^2))`
Integrate the following with respect to x:
`(3x + 1)/(2x^2 - 2x + 3)`
Integrate the following with respect to x:
`(2x + 1)/sqrt(9 + 4x - x^2)`
Choose the correct alternative:
`int ("e"^x (1 + x))/(cos^2(x"e"^x)) "d"x` is
Choose the correct alternative:
`int 2^(3x + 5) "d"x` is
Choose the correct alternative:
`int x^2 "e"^(x/2) "d"x` is
