Advertisements
Advertisements
Question
In the following figures, find the remaining angles of the parallelogram
Advertisements
Solution
ABCD is a parallelogram.
∠A = 75°
⇒ ∠C = 75° ....(Opposite angles of a parallelogram are eequal)
Now,∠A + ∠D = 180° ....(Interior angles)
⇒ ∠75° + ∠D = 180°
⇒ ∠D = 105°
⇒ ∠B = ∠D = 105° ....(Opposite angles of a parallelogram are equal)
Thus, we have
∠B = 105°, ∠C = 75° and ∠D = 105°.
APPEARS IN
RELATED QUESTIONS
In case of a parallelogram
prove that:
(i) The bisectors of any two adjacent angles intersect at 90o.
(ii) The bisectors of the opposite angles are parallel to each other.
In the given figure, AP is the bisector of ∠A and CQ is the bisector of ∠C of parallelogram ABCD. 
Prove that APCQ is a parallelogram.
In the following figure, ABCD is a parallelogram. 
Prove that:
(i) AP bisects angle A.
(ii) BP bisects angle B
(iii) ∠DAP + ∠BCP = ∠APB
In the following figures, find the remaining angles of the parallelogram
In the following figures, find the remaining angles of the parallelogram
In the following figures, find the remaining angles of the parallelogram
Find the measures of all the angles of the parallelogram shown in the figure:
The angles of a triangle formed by 2 adjacent sides and a diagonal of a parallelogram are in the ratio 1 : 5 : 3. Calculate the measures of all the angles of the parallelogram.
In the given parallelogram YOUR, ∠RUO = 120° and OY is extended to point S such that ∠SRY = 50°. Find ∠YSR.
