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Question
In reference to Freundlich adsorption isotherm, write the expression for adsorption of gases on solids in the form of an equation.
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Solution
Freundlich adsorption isotherm for adsorption of gases on solids:
xm=Kp1nIt can also be written aslogxm=log K + 1nlog p">
\[\frac{x}{m} = K p^\frac{1}{n} \]
\[\text{It can also be written as}\]
\[\log\frac{x}{m} = \log K + \frac{1}{n}\log p\]
where x is the mass of the adsorbate, m is the mass of the absorbent and p is the pressure of the gas and n is a constant which is greater than 1.
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Answer in one sentence:
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Freundlich adsorption isotherm is given by the expression `x/m = kp^(1/n)` which of the following conclusions can be drawn from this expression.
(i) When `1/n` = 0, the adsorption is independent of pressure.
(ii) When `1/n` = 0, the adsorption is directly proportional to pressure.
(iii) When n = 0, `x/m` vs p graph is a line parallel to x-axis.
(iv) When n = 0, plot of `x/m` vs p is a curve.
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Langmuir adsorption isotherm works particularly well.
