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Question
In reference to Freundlich adsorption isotherm, write the expression for adsorption of gases on solids in the form of an equation.
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Solution
Freundlich adsorption isotherm for adsorption of gases on solids:
xm=Kp1nIt can also be written aslogxm=log K + 1nlog p">
\[\frac{x}{m} = K p^\frac{1}{n} \]
\[\text{It can also be written as}\]
\[\log\frac{x}{m} = \log K + \frac{1}{n}\log p\]
where x is the mass of the adsorbate, m is the mass of the absorbent and p is the pressure of the gas and n is a constant which is greater than 1.
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Answer in one sentence:
Write an equation for Freundlich adsorption isotherm.
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Freundlich's equation for adsorption of gas on solid is represented as ____________.
In Freundlich's adsorption isotherm, when log `("x"/"m")` is plotted against log P, slope of the graph is ____________.
Freundlich adsorption isotherm is given by the expression `x/m = kp^(1/n)` which of the following conclusions can be drawn from this expression.
(i) When `1/n` = 0, the adsorption is independent of pressure.
(ii) When `1/n` = 0, the adsorption is directly proportional to pressure.
(iii) When n = 0, `x/m` vs p graph is a line parallel to x-axis.
(iv) When n = 0, plot of `x/m` vs p is a curve.
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Which of the following statement is INCORRECT regarding the adsorption of a gas on the surface of the solid?
In Freundlich adsorption isotherm, slope of AB line is:
For Freundlich adsorption isotherm, a plot of log (x/m) (Y-axis) and log p (x-axis) gives a straight line. The intercept and slope for the line is 0.4771 and 2, respectively. The mass of gas, adsorbed per gram of adsorbent if the initial pressure is 0.04 atm, is ______ × 10-4 g. (log 3 = 0.4771)
