English

In Reference to Freundlich Adsorption Isotherm, Write the Expression for Adsorption of Gases on Solids in the Form of an Equation. - Chemistry

Advertisements
Advertisements

Question

In reference to Freundlich adsorption isotherm, write the expression for adsorption of gases on solids in the form of an equation.

Advertisements

Solution

Freundlich adsorption isotherm for adsorption of gases on solids:
xm=Kp1nIt can also be written aslogxm=log K + 1nlog p">

\[\frac{x}{m} = K p^\frac{1}{n} \]

\[\text{It can also be written as}\]

\[\log\frac{x}{m} = \log K + \frac{1}{n}\log p\]

where x is the mass of the adsorbate, m is the mass of the absorbent and p is the pressure of the gas and n is a constant which is greater than 1.

shaalaa.com
  Is there an error in this question or solution?
2013-2014 (March) Delhi Set 2

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Explain graphically Freundlich adsorption isotherm.


The slope and intercept for plot of `log_10  "x"/"m"` against log10P for Freundlich equation are ____________ and ____________ respectively.


Adsorption of a gas follows Freundlich adsorption isotherm. x is the mass of the gas adsorbed on mass m of the adsorbent. The plot of log `"x"/"m"`· versus log P is shown in the given m graph. `"x"/"m"` is proportional to


In Freundlich's adsorption isotherm, when log `("x"/"m")` is plotted against log P, slope of the graph is ____________.


Freundlich adsorption isotherm is given by the expression `x/m = kp^(1/n)` which of the following conclusions can be drawn from this expression.

(i) When `1/n` = 0, the adsorption is independent of pressure.

(ii) When `1/n` = 0, the adsorption is directly proportional to pressure.

(iii) When n = 0, `x/m` vs p graph is a line parallel to x-axis.

(iv) When n = 0, plot of `x/m` vs p is a curve.


Adsorption of gases on the solid surface is generally exothermic because.


Langmuir adsorption isotherm works particularly well.


In the freundilch adsorption isotherm, the value of x/m is 0.4 under a pressure of 0.2 at m calculate the value of the interact


Adsorption of a gas follows Freundlich adsorption isotherm. x is the mass of the gas adsorbed on mass m of the adsorbent. The x plot of log `x/m` versus log p is shown in the given graph. `x/m` is proportional to ______.


For Freundlich adsorption isotherm, a plot of log (x/m) (Y-axis) and log p (x-axis) gives a straight line. The intercept and slope for the line is 0.4771 and 2, respectively. The mass of gas, adsorbed per gram of adsorbent if the initial pressure is 0.04 atm, is ______ × 10-4 g. (log 3 = 0.4771)


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×