Advertisements
Advertisements
Question
How is activation of adsorbent achieved?
Advertisements
Solution
- By increasing the surface area of the adsorbent. This can be done by breaking it into smaller pieces or powdering it.
- Some specific treatments can also lead to the activation of the adsorbent. For example, wood charcoal is activated by heating it between 650 K and 1330 K in a vacuum or air. It expels all the gases absorbed or adsorbed and thus creates a space for adsorption of gases.
RELATED QUESTIONS
What is an adsorption isotherm?
Describe Freundlich adsorption isotherm.
In reference to Freundlich adsorption isotherm, write the expression for adsorption of gases on solids in the form of an equation.
Explain graphically Freundlich adsorption isotherm.
The slope and intercept for plot of `log_10 "x"/"m"` against log10P for Freundlich equation are ____________ and ____________ respectively.
Adsorption of a gas follows Freundlich adsorption isotherm. x is the mass of the gas adsorbed on mass m of the adsorbent. The plot of log `"x"/"m"`· versus log P is shown in the given m graph. `"x"/"m"` is proportional to
Freundlich's equation for adsorption of gas on solid is represented as ____________.
Which of the following curves is in accordance with Freundlich adsorption isotherm?
Freundlich adsorption isotherm is given by the expression `x/m = kp^(1/n)` which of the following conclusions can be drawn from this expression.
(i) When `1/n` = 0, the adsorption is independent of pressure.
(ii) When `1/n` = 0, the adsorption is directly proportional to pressure.
(iii) When n = 0, `x/m` vs p graph is a line parallel to x-axis.
(iv) When n = 0, plot of `x/m` vs p is a curve.
Adsorption of gases on the solid surface is generally exothermic because.
In the freundilch adsorption isotherm, the value of x/m is 0.4 under a pressure of 0.2 at m calculate the value of the interact
In Freundlich adsorption isotherm, slope of AB line is:
The mass of gas adsorbed, x per unit mass of adsorbed, m was measured at various x pressures p. A graph between `log "x"/"m"` and log p gives a straight line with slope equal to 2 and the intercept equal to 0.4771. The value of `"x"/"m"` at a pressure of 4 atm is ______.
[Given log 3 = 0.4771]
For Freundlich adsorption isotherm, a plot of log (x/m) (Y-axis) and log p (x-axis) gives a straight line. The intercept and slope for the line is 0.4771 and 2, respectively. The mass of gas, adsorbed per gram of adsorbent if the initial pressure is 0.04 atm, is ______ × 10-4 g. (log 3 = 0.4771)
